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the number will be represented in the form of (-1)^s(0.M)*16^(E-64).the range of exponent can be given as (-128 to 127) because exponent is 8 bit signed number(2's complement).am i right?????
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32 bit means single precision floating point number

Where exponent will be of 8 bits

So, range of exponent will be $-2^{8-1}-1$ to $2^{8-1}$ i.e.$-127$ to $128$
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Its mentioned that there is signed exponent, hence range will be from -127 to 127.

If exponent is excess 127 then the range becomes 0 to 254

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