@iarnav , range of exponents will be from -126 to +127 if we take 32-bit single precision floating point number in implicit normalised binary form because for this form ,
1 $\leq$ E $\leq$ 254 , So, range of exponent will be 1-127 = -126 to 254-127 = +127 because here bias is 127 (i.e. bias is in Excess-127 format)
But here , excess-64 format is given . so bias = 64
and since single precision floating point number is not mentioned , so we have to take 0 $\leq$ E $\leq$ 255 .so, range of exponent is from 0 - 64 = -64 to 255-64 = +191.. I am not getting the meaning of "The base of the scale factor is 16" . if you know then please explain.