0 votes 0 votes Q) Let the binary sum after BCD addition is stored in K, Z8, Z4, Z2, and Z1. Then the condition for a correction and output carry can be expressed as C = A) K + Z8 Z4 + Z8 Z2 B) K + Z8 Z4 + Z4 Z2 C) K + Z8 Z2 + Z8 Z1 D) K + Z4 Z2 + Z2 Z1 CO and Architecture bcd co-and-architecture number-system + – shaz asked Jul 22, 2018 shaz 1.4k views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply MiNiPanda commented Jul 22, 2018 reply Follow Share Is it A ? 0 votes 0 votes shaz commented Jul 22, 2018 reply Follow Share Yes. Could you please explain the logic? 0 votes 0 votes MiNiPanda commented Jul 23, 2018 reply Follow Share Since it will be very time consuming to draw a K-map of 5 variables, you can do it in this way i.e. by dividing Z8Z4Z2Z1 in two groups -> one in which K=0 and other in which K=1. So for instance, the cell 3 in 2nd K-map corresponds to 1 0011 i.e. KZ8'Z4'Z2Z1. We don't have any row in the Truth Table for numbers>19. So we put don't care in the cells where Z8Z4Z2Z1>0011. For eg.Z8Z4Z2Z1=0100 i.e. K Z8Z4Z2Z1=1 0100 = (20)10 2 votes 2 votes Please log in or register to add a comment.
Best answer 1 votes 1 votes we add bcd correction if there is a final carry 1001 + 1001 --------------------- 1 0010 here K=1 hence we add 0110 for correction the result of sum of individual bcd digit is greater than 9 0110 + 0011 ------------------------ 1010 here the result is 1010 which is 10 in binary but not in bcd. to correct it add 0110 hence for correction to be added either K = 1 or result out of range for the following cases we'll get out of range $z_8$$z_4$$z_2$$z_1$ 1010 1011 11xx which is $z_8$$z_2$ + $z_8$$z_4$ option A) K + $z_8$$z_2$ + $z_8$$z_4$ is correct Ananya Jaiswal 1 answered Jul 23, 2018 selected Jan 21, 2019 by shaz Ananya Jaiswal 1 comment Share Follow See all 0 reply Please log in or register to add a comment.