Value at an Address

Question

Answer 1

$32$ bits means $4$ bytes which are as follows

$01\quad bd\quad 2d\quad 0d$

Little endian means, lower byte is at smallest address. So, the bytes read in the more significant order will be 

$0d\quad 2d\quad bd\quad 01 = 00001101\;00101101\;10111101\;00000001$

You can convert this to Decimal :)

Comments

sir, it is given that already the machine is little endian

then ac is the MSB and dd is the LSB,  for the oxa72e20 , right?

 

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Each line is having 16 bytes not 4.

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yes sir,

oxa72e20 : ac 67 36 ef 46 d9 6b c1 79 01 bd 2d 0d c6 29 dd

1010 1100 0110 0111 0011 0110 1110 1111 0100 0110 1101 1001 0110 1011 1100 0001 0111 1001 0000 0001 1011 1101 0010 1101 0000 1101 1100 0110 0010 1001 1101 1101

given that initially it is represent in x86-64 architecture ===> 64 bits for a word

therefore there are 2 words per line.

 

sir, upto this point i am getting, please complete this... and give total explanation if i am wrong