21 votes 21 votes Identify the logic function performed by the circuit shown in figure. exclusive OR exclusive NOR NAND NOR None of the above Digital Logic gate1993 digital-logic combinational-circuit circuit-output normal + – Kathleen asked Sep 29, 2014 • recategorized Apr 22, 2021 by Lakshman Bhaiya Kathleen 9.0k views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply Manu Thakur commented Dec 15, 2017 reply Follow Share Simplify the given circuit: 4 votes 4 votes Anu007 commented Dec 15, 2017 i edited by Anu007 Dec 15, 2017 reply Follow Share there is one more easy method. shaded region works as Two level OR And ; now you need to do : [x+(x'y')] And [y +(x'y')] = [x+y'] And [y+ x']= xy+x'y' 0 votes 0 votes Manu Thakur commented Dec 15, 2017 reply Follow Share @anu shaded portion is same as in the comment posted by me? 1 votes 1 votes Lakshman Bhaiya commented Oct 14, 2019 reply Follow Share NOR-NOR Realization is same as OR-AND realization. 2 votes 2 votes Please log in or register to add a comment.
Best answer 20 votes 20 votes $(x+x'y') .(y+x'y') = (x+y')(x'+y) = xy + x'y' = \text{Exclusive-NOR}$ Praveen Saini answered Feb 27, 2015 • selected Feb 28, 2015 by Arjun Praveen Saini comment Share Follow See all 4 Comments See all 4 4 Comments reply Puja Mishra commented Feb 7, 2017 reply Follow Share johnson counter ??????????? 0 votes 0 votes Sunidhi chauhan commented Sep 24, 2017 reply Follow Share HOW EXCLUSIVE NOR PLZ SIR TELL THIS STEP BY STEP? 0 votes 0 votes Parth Shah commented May 31, 2018 reply Follow Share @Arjun sir please modify this answer as question demands for identifying the logic function based on circuit and in answer part explanation for 6.2 and 6.3 is given which is not required. 1 votes 1 votes Abir Mazumder commented Sep 28, 2020 reply Follow Share For EX-NOR of 2 boolean variable if we simply replace the variables with their complement , the value remains same . F = a.b + a’.b’ – > replace a with a’ and b with b’ – > a’.b’ + ab We will be using this theory here . Now , look at the 3 XNOR gates from right . If we simply imagine that the ‘NOT’ from first 2 XNOR and is taken and made as a NOT gate to the inputs of the final XNOR gate then the final XNOR doesn’t change and the other 2 XNOR becomes XOR . then the boolean formula becomes something like , XNOR(XOR(x,XNOR(x,y)), XOR(y,XNOR(x,y))) = NOT(XOR(XOR(x,XNOR(x,y)) , XOR(y,XNOR(x,y)))) = NOT(XOR(x,XOR(x,y),y,XOR(x,y))) = XNOR(x,y) 0 votes 0 votes Please log in or register to add a comment.
7 votes 7 votes ANS: B ( (x+(x+y)')' + (y+(x+y)')' )' =xy +x'y' mohitbawankar answered Oct 4, 2017 • edited Oct 4, 2017 by mohitbawankar mohitbawankar comment Share Follow See all 0 reply Please log in or register to add a comment.