Gate academy test series

Question

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Possible solution

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Generally, Paging is applied on Segment Table but not on the Segments....

But in this question, gives that 

Page table of segment fits exactly

we can conclude that paging is applied on segment, therefore given solution is correct.

 

If question is  

Page table of segment table fits exactly

for solving this we require Segment Table Entry size 

Answer 1

vas = 2^32

divided into 32 segments = 2^5

size of each segment  = 2^32/2^5 = 2^(32-5)= 2^27

let page size be 2^x , then no of pages in one segment = 2^27/2^x = 2^(27-x)

no of entries in page table for one segment = 2^(27-x)

size of each entry = 8B = 2^3B

total size of page table = 2^(27-x)*2^3 = 2(27-x+3)= 2^(30-x)

now as it should fit in one page so 2^(30-x) = 2^x => base are same so exponent are also same

30-x = x => 2x = 30 = >x = 15

page size 2^x = 2^15 = 32KB

option d