Problem solving

Question

Two students appeared at an explanation. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are?

Answer 1

Let their marks be $x+9$  and $x$.

Then,

$x+9 = \dfrac{56}{100}.(x + 9 + x)$

$\Rightarrow 25.(x+9) = 14.(2x + 9)$

$\Rightarrow 3x = 99$

$\Rightarrow x = 33$

So, their marks are $42$ and $33$.

Answer 2

Let the marks of two students be x and (x+9)

Sum of marks=2x+9

According to the given question: 56% of (2x+9)=x+9

On solving we get x=33.

Therefore the marks are 33 and 42

* I assume it's examination instead of explanation