C Programing mock test geeks for geek

Question

int main()
{
    int a[10];
    printf("%d",*a+1-*a+3);
    return 0;
}

Answer is given as 4 but i think it should be 8, if int is of 4 byte. Correct me if i am wrong

Comments

Can you explain how are you getting 8?

Here *a is used and not just 'a'. So we are not dealing with any address. *a means a[0]. We don't know what is it. But let it be some x. Then (*a+1-*a+3) = (x+1-x+3)=4.

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Yes, answer should be 4

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@Gatetarget_100

What my suggestion is " When you see an complex expression, first you simplify it and parenthesize it. "

*a+1-*a+3 ==> ( (  ( (*a) + 1 )  - (*a) )  + 3 )

Now, you have to evaluate *a first,

*a = *(a+0) = a[0]

after that just like @ MiNiPanda says

We don't know what is it. But let it be some x. Then (*a+1-*a+3) = (((x+1)-x)+3) = 4.

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Got it Thanku :)