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Consider the size of congestion window of a TCP connection be 36 KB when a timeout occurs. The round trip time of the connection is 200 μsec and the maximum segment size used is 2 KB. What is the time taken by the TCP connection to get back to 36 KB congestion window?
asked in Computer Networks by (319 points) | 26 views
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$2 | 4 | 8 | 16 | 18 | 20 | 22 | 24 | 26 | 28 | 30 | 32 | 34 | 36$

$13 \times 200 = 2600μsec$

1 Answer

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WHEN TIME OUT OCCUR SENDER WINDOW SIZE = 1 MSS = 2KB

THRESHOLD VALUE = 9 MSS = 18 KB

SO 1MSS,2MSS,4MSS,8MSS,9MSS,10MSS,11MSS,12MSS,13MSS,14MSS,15MSS,16MSS,17MSS,18MSS.

-> TOTAL TIME = 14*200 = 2800 MICOSEC
answered by (231 points)


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