can u please make options more clearer and even option B and C are same.

Dark Mode

0 votes

since , T(1)=K (given)

T(2)=3T(1)+2K=5K

T(4)=3T(2)+4k=19K .... SO...on

putting these values in option 2...

T(1)= 3k n^{log}^{23} - 2kn (since n^{log}^{23} == 3^{log}^{2n}== 1)

=3*k*1 - 2k*1 == k

similarly,

T(2)= 3k^{log}^{23} - 2kn ( 3^{log}^{2n} == 3)

= 3*k*3 - 2*k*2 = 5k

and so..on . so answer is **B**