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The round trip propagation delay for a 100Mbps Ethernet having 48-bit jamming signal is 64 ms. What is the minimum frame size (in bytes)?

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WHENVER THERE IS COLLISION THEN JAMMING SIGNAL IS USED UPTO 2PT.

FOR CALCULATING MIN FRAME SIZE WE USE TT = 2*PT

GIVEN RTT = 2*PT = 64 MILLISEC

LET FRAME SIZE = X BITS

-> X/100*10^6 = 64*10^-3

-> X = 64 * 10^5 BITS = 8*10^5 BYTE = 800000 BYTES

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