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Madeeasy_Subject_Test_digitalLogic

+2 votes
88 views

asked in Digital Logic by Loyal (9.4k points) | 88 views

2 Answers

+3 votes

@arvin already showed a nice way. Still I am answering as what I understands... 

201 = (11001001)

so can be represented  in IEEE 754 standard double precision (Excess 1023) (https://en.wikipedia.org/wiki/Double-precision_floating-point_format) as 

1.1001001000...0 * 21030

So next number in sequence is to add 1 to above number i.e. 52th bit is 1 in mantissa. So difference will be

0.0000...1 * 21030  = 1* 2978 

So a number 1 * 2978 of double precision (Excess 1023) can be represented in decimal as 

1 * 2978-1023 = 1 * 2-45

So answer is -45 

answered by Active (1.3k points)
+1 vote

A Double precision(64bits) format means it has 1bit for sign 11bits for exponent and 52bits for significand.

The binary floating point representation of 201 is (1.1001001)2 × 2 7 .  so the gap between this number and the next larger double precision floating point number is (1.1001001+2−52 )× 2 7

= 2−45 

-45 is the answer.

 

answered by Loyal (9.5k points)
0
Correct approach
0

thanks arvin  ..but i didn,t understand the term next larger double precision ...what's that mean ????

+1

@pankaj thanku :) 

.

@magma : its just like next number to (1.10000)2 is (1.10001)2

==> (1.10001)2=(1.10000* 2-5)2

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