c programming

Question

what is the output of the c program given below,
 

#include<stdio.h>
int main()
{
    char pt[]="Gatelecture";
    char qt[]="GATE";
    int i=0;
    for( ;pt[i++]=qt[i++]; );
    printf("%s",pt);
}

 

a. AeEe

b. AaEe

c. aAeE

d. none of the above

Comments

so , no segmentation fault

only undefined behavior for different compiler

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@Minipanda

I am getting" GaTe" as output

And as Arvin said he is getting "AaEelecture" on online compiler so it should be undefined behaviour

As different compiler are showing different output

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Yup

Answer 1

Undefined behavior in C. Answer is compiler dependent.

Hence, the correct answer must be d) None of the above.

Comments

ASCII values of character returns if you are assigning them the integer right?

ex:- int a='A'; ===> int a=65 (Both are equivalent if the range is <128)

ASCII value of '\0' is 0

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Okk.. I don't know why but my laptop is also showing it will go into infinite loop. I'm using gcc 4.9.2 :/

The answer is compiler dependent I guess.

Thanks for having a detailed conversation :)

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note that, i shows undefined behavior.... therefore i may not assign the value as 4 in your compiler... at 4th index only we have null ===> if you didn't get that index to i, you are in infinite loop

if your compiler shows infinite loop, then print i value in the loop....you should didn't encounter i=4