12 votes 12 votes Consider the below function $f=\sum m(0,1,2,5,8,15)+d(6,7,10)$ In this Prime Implicant count comes-7 and Essential Prime Implicant Count comes 2. Please verify. Digital Logic digital-logic + – Ayush Upadhyaya asked Aug 14, 2018 Ayush Upadhyaya 5.5k views answer comment Share Follow See all 38 Comments See all 38 38 Comments reply Show 35 previous comments Verma Ashish commented Dec 13, 2019 reply Follow Share 1,5 is not a epi, because there is no '1' which can't be combined in other way.. (I am not receiving emails notification for comments :( 3 votes 3 votes techbd123 commented Dec 13, 2019 reply Follow Share @Verma Ashish That's the correct explanation. 1 votes 1 votes `JEET commented Dec 13, 2019 reply Follow Share Thanks, @Verma Ashish @techbd123 1 votes 1 votes Please log in or register to add a comment.
Best answer 7 votes 7 votes Everything that I concluded- Please correct me if I am wrong somewhere. Soumya29 answered Aug 16, 2018 • selected Aug 18, 2018 by Shaik Masthan Soumya29 comment Share Follow See all 16 Comments See all 16 16 Comments reply Shaik Masthan commented Aug 16, 2018 reply Follow Share mam, i have a basic doubt that Why can't you form sub-cube with 0's 0 votes 0 votes Soumya29 commented Aug 16, 2018 reply Follow Share If I form subcubes of 0's also then nothing will be left. ? 0 votes 0 votes Shaik Masthan commented Aug 16, 2018 reply Follow Share i mean, for f(x,y,z) = ∑ (0,1) + ∅ (2,6) if we form sub cubes for zero's====> we are getting only 2 right ? 0 votes 0 votes Soumya29 commented Aug 16, 2018 reply Follow Share Why are you forming subcubes of 0's ? 0 votes 0 votes Shaik Masthan commented Aug 16, 2018 reply Follow Share function can be represent by pos form also... i want to go in that way... what's wrong in that? 0 votes 0 votes Soumya29 commented Aug 16, 2018 reply Follow Share Yeah. In that case we will get 3 by f1 right ? 0 votes 0 votes Shaik Masthan commented Aug 16, 2018 reply Follow Share but i am getting only 2... 1) 100,101,111,110 2) 011,010,111,110 0 votes 0 votes Soumya29 commented Aug 16, 2018 reply Follow Share Yes, in pos it's 2. But Is it necessary to have equal no. of PIs in Sop as well as pos.? It's not .. 0 votes 0 votes Shaik Masthan commented Aug 16, 2018 reply Follow Share Then my question arises that is it 2 or 3, because in the question they didn't mention it is sop or pos 0 votes 0 votes Soumya29 commented Aug 16, 2018 reply Follow Share It's SOP and 3 PIs 0 votes 0 votes ankitgupta.1729 commented Aug 16, 2018 reply Follow Share @Shaik Masthan , In the given question , it is mentioned sigma sign . So , we have to take minterms and make switching expression in sop form. If it is pi sign, then we will take maxterms and form switching expression in pos 1 votes 1 votes Soumya29 commented Aug 17, 2018 reply Follow Share @Shaik . Here is a nice question for you - Now tell us the number of PIs here. And their minterms and expression too. 1 votes 1 votes Shaik Masthan commented Aug 17, 2018 reply Follow Share mam, i doesn't ask that question Then my question arises that is it 2 or 3, because in the question they didn't mention it is sop or pos not only for this question, it applicable to your above example also... i mean i asked that in general. @ankitgupta.1729, Brother why not question convert in to pi symbol? 0 votes 0 votes Shaik Masthan commented Aug 17, 2018 reply Follow Share @ankitgupta.1729, they are asking about EPI's... in ∑ to ∏ also i am getting 3 only. 0 votes 0 votes Ayush Upadhyaya commented Aug 22, 2018 reply Follow Share @Soumya-The answer to the question that you given to shaik Number of PI are 3 $[xz(E),wz,w\lnot x(E)]$ Essential PI are indicated by (E) minimal form=$xz+w\lnot x$ is answer correct? 3 votes 3 votes Vimal Patel commented Dec 7, 2019 reply Follow Share I have one doubt. Definition of implicant is that if it is true then function must be true. Then if we consider that all x's can be combined to give prime implicant but does that prime implicant implies function? 0 votes 0 votes Please log in or register to add a comment.