1 votes 1 votes I think the answer given here is wrong , Magma asked Aug 16, 2018 Magma 232 views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments Magma commented Aug 16, 2018 reply Follow Share No Jason I think you done that in a wrong way 0 votes 0 votes Shaik Masthan commented Aug 16, 2018 reply Follow Share @Magma, The solution provided by them should be wrong... Note that given Process Size = 232. and Page Size = 1 Kb = 210 b = 27 Bytes no.of pages in the process ( no.of entries in PT1 ) = $\frac{2^{32}}{2^{7}}$ = ${2^{25}}$ ===> Size of 1st level Page Table = ${2^{25}}$ * 22 B = ${2^{27}}\;B$ no.of pages in the PT1 ( no.of entries in PT2 )= $\frac{2^{27}}{2^{7}}$ = ${2^{20}}$ ===> Size of 2nd level Page Table = ${2^{25}}$ * 22 B = ${2^{22}}\;B$ no.of pages in the PT2 ( no.of entries in PT3 ) = $\frac{2^{22}}{2^{7}}$ = ${2^{15}}$ ===> Size of 3rd level Page Table = ${2^{25}}$ * 22 B = ${2^{17}}\;B$ no.of pages in the PT3 ( no.of entries in PT4 ) = $\frac{2^{17}}{2^{7}}$ = ${2^{10}}$ ===> Size of 4th level Page Table = ${2^{10}}$ * 22 B = ${2^{12}}\;B$ no.of pages in the PT4 ( no.of entries in PT5 ) = $\frac{2^{12}}{2^{7}}$ = ${2^{5}}$ ===> Size of 5th level Page Table = ${2^{5}}$ * 22 B = ${2^{7}}\;B$ ===> Fit in 1 Page Over Head By page tables = $ ({2^{27}} + {2^{22}} + {2^{17}} + {2^{12}} + {2^{7}} ) \;B$ 2 votes 2 votes Magma commented Aug 16, 2018 reply Follow Share thanks Shaik Masthan you explanations are just awsome and easy to understand 0 votes 0 votes Please log in or register to add a comment.