At First we can choose Either P0 or P4,therefore 2C1 choices
Either we choose P0 or P4,we need to choose 1 Out of 3(Except P1 we can choose any process) hence 3C1 choices
After that,we again choose 1 process out of 3(this time P1 will be available) hence 3C1 choices
Now we are left with only 2 process hence 2C1 choices
Therefore Answer is 2C1x3C1x3C1x2C1=36