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At First we can choose Either P0 or P4,therefore 2C1 choices

Either we choose P0 or P4,we need to choose 1 Out of 3(Except P1 we can choose any process)  hence 3C1 choices

After that,we again choose 1 process out of 3(this time P1 will be available) hence 3C1 choices

Now we are left with only 2 process hence 2C1 choices

Therefore Answer is 2C1x3C1x3C1x2C1=36

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