for T(m) = aT(m/b) + mklogpm
a = 1 (satisfies, required a >=1)
b=4/3 (satisfies, required b>1)
k = 0 (satisfies, k>=0)
p=0 (satisfies, required p can be any real number)
we can Apply master's Theorem
now comparing a and bk ,we will get a = bk
so, go for case when a = bk and p > -1
we get T(m)= ⊖(mlogbalog p+1m) = ⊝(mlog4/31log m) = ⊝ (log m)