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in Digital Logic by Active (1.8k points)
edited by | 112 views
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Is it B?
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I am getting (261) base [email protected] are you getting exactly 251?
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Got it now
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the ans is b.
+2

266+1 ≠ 267. As it is base=7 so the digits can't be >=7.

So 7 has to be written in base 7 form which is

71 70
1 0

 

i.e. 10. sum=0 and carry=1.

Again 6+1(carry) = 10 => sum=0 and carry=1

2+1=3 sum=3 carry=0

So, 266+1 = (300)7

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thanx #MiNiPanda
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Thanks for the explanation
+3

Shubham Aggarwal  Do let me know if you can understand this

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Best explanation....

1 Answer

+3 votes
Best answer
$[507]_{9} 8's$ complement $=888-507=[381]_{9}=[316]_{10}=[474]_{8}$=P

$[400]_{7} 7''s$ complement$=[223]_{8}$=Q

by subtracting q from p we get $[251]_{8}$
by Active (2.8k points)
edited by
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(400)7 =(223)8 how are you getting this plz explain.?
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(r-1)'s complement=$[666-400]_{7}=[266]_{7}$ but we need 7's complement so add 1 to the 266+1=$[300]_{7}$=$[147]_{10}$=$[223]_{8}$
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