Ace Test Series: Digital Logic - Number System

Question

Comments

Thanks for the explanation

---

Shubham Aggarwal  Do let me know if you can understand this

---

Best explanation....

Answer 1

$[507]_{9} 8's$ complement $=888-507=[381]_{9}=[316]_{10}=[474]_{8}$=P

$[400]_{7} 7''s$ complement$=[223]_{8}$=Q

by subtracting q from p we get $[251]_{8}$

Comments

(400)7 =(223)8 how are you getting this plz explain.?

---

(r-1)'s complement=$[666-400]_{7}=[266]_{7}$ but we need 7's complement so add 1 to the 266+1=$[300]_{7}$=$[147]_{10}$=$[223]_{8}$