in Digital Logic edited by
657 views
0 votes
0 votes

in Digital Logic edited by
657 views

4 Comments

Thanks for the explanation
0
0

Shubham Aggarwal  Do let me know if you can understand this

3
3
Best explanation....
0
0

1 Answer

3 votes
3 votes
Best answer
$[507]_{9} 8's$ complement $=888-507=[381]_{9}=[316]_{10}=[474]_{8}$=P

$[400]_{7} 7''s$ complement$=[223]_{8}$=Q

by subtracting q from p we get $[251]_{8}$
edited by

2 Comments

(400)7 =(223)8 how are you getting this plz explain.?
0
0
(r-1)'s complement=$[666-400]_{7}=[266]_{7}$ but we need 7's complement so add 1 to the 266+1=$[300]_{7}$=$[147]_{10}$=$[223]_{8}$
0
0

Related questions