0 votes 0 votes Digital Logic ace-test-series digital-logic number-system + – Shubham Aggarwal asked Aug 20, 2018 edited Mar 3, 2019 by I_am_winner Shubham Aggarwal 1.1k views answer comment Share Follow See all 10 Comments See all 10 10 Comments reply MiNiPanda commented Aug 20, 2018 reply Follow Share Is it B? 0 votes 0 votes Bhagyashree Mukherje commented Aug 20, 2018 reply Follow Share I am getting (261) base 8.@MiNiPanda are you getting exactly 251? 0 votes 0 votes MiNiPanda commented Aug 20, 2018 reply Follow Share Bhagyashree Mukherje Yes 0 votes 0 votes Bhagyashree Mukherje commented Aug 20, 2018 reply Follow Share Got it now 0 votes 0 votes Shubham Aggarwal commented Aug 20, 2018 reply Follow Share the ans is b. 0 votes 0 votes MiNiPanda commented Aug 20, 2018 reply Follow Share 266+1 ≠ 267. As it is base=7 so the digits can't be >=7. So 7 has to be written in base 7 form which is 71 70 1 0 i.e. 10. sum=0 and carry=1. Again 6+1(carry) = 10 => sum=0 and carry=1 2+1=3 sum=3 carry=0 So, 266+1 = (300)7 2 votes 2 votes Shubham Aggarwal commented Aug 20, 2018 reply Follow Share thanx #MiNiPanda 0 votes 0 votes Bhagyashree Mukherje commented Aug 20, 2018 reply Follow Share Thanks for the explanation 0 votes 0 votes MiNiPanda commented Aug 20, 2018 reply Follow Share Shubham Aggarwal Do let me know if you can understand this 3 votes 3 votes Shubham Aggarwal commented Aug 21, 2018 reply Follow Share Best explanation.... 0 votes 0 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes $[507]_{9} 8's$ complement $=888-507=[381]_{9}=[316]_{10}=[474]_{8}$=P $[400]_{7} 7''s$ complement$=[223]_{8}$=Q by subtracting q from p we get $[251]_{8}$ BASANT KUMAR answered Aug 20, 2018 edited Nov 21, 2019 by srestha BASANT KUMAR comment Share Follow See all 2 Comments See all 2 2 Comments reply Shubham Aggarwal commented Aug 20, 2018 reply Follow Share (400)7 =(223)8 how are you getting this plz explain.? 0 votes 0 votes BASANT KUMAR commented Aug 20, 2018 reply Follow Share (r-1)'s complement=$[666-400]_{7}=[266]_{7}$ but we need 7's complement so add 1 to the 266+1=$[300]_{7}$=$[147]_{10}$=$[223]_{8}$ 0 votes 0 votes Please log in or register to add a comment.