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Which one is equivalent to p->q->r ?
A) (p->q)->r
B) p->(q->r)
Plz give answer with proper explaination.

1 Answer

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implication is not associative.

p→(q→r)≠(p→q)→r

Convention is that for p→q→r take implication as right associative..i.e. p→q→r= p→(q→r).

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