Let Us C- Q2.43

Question

Output will be-

int main(){ int a =0,b=1,c=3:

*((a)?&b&:&a)=a ? b : c;

printf("%d %d%d ", a,b,c);

}

Comments

3 1 3 ?

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Please explain how?

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*((a)?&b&:&a)=a ? b : c;
 

The & is extra..

The right side of assignment operator is evaluated first. So, a ? b : c means 0?b:c => False?b:c

so as per the ternary operation this will be evaluated to the value of c i.e. 3.

Now evaluate the lhs:

Let &a=100,&b=200,&c=300

*((a)?&b:&a) = *((0)?&b:&a) = *(&a)= *100

*100 i.e. a will be evaluated with rhs i.e. 3.

a=3,b=1,c=3

So output will be 3 1 3.

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Got it.Thanks a lot for explanation.