in Quantitative Aptitude edited by
6,464 views
12 votes
12 votes

$25$ persons are in a room. $15$ of them play hockey, $17$ of them play football and $10$ of them play both hockey and football. Then the number of persons playing neither hockey nor football is:

  1. $2$
  2. $17$
  3. $13$
  4. $3$
in Quantitative Aptitude edited by
6.5k views

5 Answers

15 votes
15 votes
Best answer

D. 3
No. of persons who play either football or hockey $= 15 + 17 - 10 = 22$
No. of persons playing neither hockey nor football  $= 25 - 22 = 3$

selected by
by
4 votes
4 votes

Apply Principle of mutual Inclusion $-$Exclusion

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

edited by

1 comment

this is more understandable than other methods, as this can be used in any other this type of questions, i was just looking for this kind of solution, Thank You
1
1
2 votes
2 votes
(D)3;

Explanation- number of player=25,

player who play either football or hockey=17+15,

play both hockey and football=10.

then players who play=32-10=22

then players who do not play =25-22=3;
2 votes
2 votes
no.of persons only play hockey =15-10=5
no. of persons only play  football =17-10=7
no.of persons play both hockey and football=10
so,total no of persons play hockey and football =5+7+10=22
therefore,total no. of persons neither play hockey nor football=25-22=3
by
Answer:

Related questions

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true