0 votes 0 votes Computer Networks computer-networks fragmentation + – kallu singh asked Aug 24, 2018 • retagged May 20, 2021 by Shiva Sagar Rao kallu singh 334 views answer comment Share Follow See 1 comment See all 1 1 comment reply Shubhgupta commented Aug 24, 2018 reply Follow Share As given in the question MTU size is 200 at router which contains 20 bytes of IP header Total data bytes - 600 1st fragment - 20 176 total size of of fragment should be divisible by 8(concept called scaling) offset - 0 2nd fragment - 20 176 offset - 0 + 176(data bytes of first fragment)/8 =22 3rd fragment - 20 176 offset - 22 + 176(data bytes of second fragment)/8 =44 4th fragment - 20 72 offset - 44 + 176(data bytes of third fragment)/8 = 66 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes For 1st question answer is d and for 2nd one b SHUBHAM SHASTRI answered Aug 24, 2018 SHUBHAM SHASTRI comment Share Follow See all 0 reply Please log in or register to add a comment.
