Counter

Question

A MOD-2 ripple counter is cascaded with a MOD-8 synchronous counter. The resulting circuit will form a counter of MOD = ___________.

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my problem is how can a asynchronous counter work like an synchronous counter?  diagram required with explanation for clearity

Answer 1

Basic Point :-

MOD-n counter means the output wave form frequency = $\frac{F_{CLK}}{n}$

 

cascaded means output of previous circuit is input to next circuit.

therefore MOD-2 ripple counter is cascaded with a MOD-8 synchronous counter means

the output of MOD-2 counter, give as input clock of the MOD-8 counter

===> output wave form frequency = $\frac{\LARGE F_{input\; CLK\; of\; MOD-8 }}{8}$ --(1)

input clock of MOD-8 counter = output of MOD-2 counter = $\frac{F_{CLK}}{2}$ ----- substitute in (1)

===> output wave form frequency = $\frac{F_{CLK}}{2*8}$ = $\frac{F_{CLK}}{16}$ ===> MOD-16 counter

Comments

@Shaik Masthan, PLEASE HELP me with this kind of question.

What I understood by your answer and this answer https://gateoverflow.in/73914/counters-frequency 

output frequency is F(initial)/ N, where N comes from mod-N, i.e, the number of distinct states.

I cannot understand why in this question https://gateoverflow.in/177869/output-clock-frequency N = 2. There are 3 distinct states, then why is it MOD N?

 

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It is not direct question... draw it using waveform, then you can easily get it.

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@Shaik Masthan

MOD counter can work for synchronous counter, as well as for asynchronous counter too. 

I read previously count sequence only for synchronous counter.

Is it right??

Here I too have that doubt https://gateoverflow.in/2117/gate2011-15