Ace test series

Question

Answer 1

Normalized Mantissa = 1.M

Minimun Mantissa = All 0's in M

Normalized Mantissa = 1.000000=1

Maximum Mantissa(Normalized)(1.M)=1.111111 =1111111* 2^-6 (to make it integer)

=(2⁷-1)*2^-6 = (2 - 2^-6)

Range = 1 to (2 - 2^-6)

Comments

And what about the exponent Sajid Ali  ???

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What I think ,

Excess Exponent = 9 bits

then ,  excess  = 256

Smallest number represented = Mantissa = 000000 and exponent = 000000000

Largest number represeted  = Mantissa  = 111111 and exponent =  111111111

therefore range of the magnitute of the implicit normalized numbers =

(1 X 2^ -256  to   ( (2 - 2^-6) X 2^ (511-256) )

=>(  (1 X 2^ -256  to   ( (2 - 2^-6) X 2^ (255) )  )

I may be wrong but why we shouldn't include the exponent part in this ??????

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Thanks Sajid sahab nice explanation