In supernetting we need network id of first block of supernet and supernet mask to find out number of blocks in supernet and define their range so here
Supernet mask 255.255.248 has 21 1's
and default supernet mask for class C have 24 1's (255.255.255.0)
so there is difference of 3 1's that's why number of blocks present are 2^3=8.
its range is from 205.16.32.0 to 205.16.39.0
where first address is 205.16.32.0 and last address is 205.16.39.255.