1 votes 1 votes A full adder can be implemented with half adder and OR gate. A 4-bit full adder without any initially carry require? a) 8 half adder 4 OR gate b) 7 half adder 4 OR gate c) 8 half adder 3 OR gate d) 7 half adder 3 OR gate Digital Logic digital-logic + – Shubham Aggarwal asked Sep 3, 2018 Shubham Aggarwal 419 views answer comment Share Follow See 1 comment See all 1 1 comment reply Shaik Masthan commented Sep 3, 2018 reply Follow Share check the comments https://gateoverflow.in/230970/work-book if you get it, then close your question 0 votes 0 votes Please log in or register to add a comment.
Best answer 0 votes 0 votes Is it D FA . FA . FA . HA For 1 full adder using HA 2 Half adder required and 1 OR gate So 2+2+2+1=7 half adder And 1+1+1 =3 OR gate Nitesh Choudhary answered Sep 3, 2018 • selected Sep 3, 2018 by Shubham Aggarwal Nitesh Choudhary comment Share Follow See all 4 Comments See all 4 4 Comments reply Nitesh Choudhary commented Sep 3, 2018 reply Follow Share For initial we use direct half adder because no carry 0 votes 0 votes Shubham Aggarwal commented Sep 3, 2018 reply Follow Share yes 0 votes 0 votes Shubham Aggarwal commented Sep 3, 2018 reply Follow Share but there is direct formula for (2n-1)H.A +(n-1) OR gates . 1 votes 1 votes Nitesh Choudhary commented Sep 3, 2018 reply Follow Share this is simple so no need to remember formula because in next question my change something 0 votes 0 votes Please log in or register to add a comment.