For Reflexivity Property:
Suppose , function $f$ supported this property, $f\left ( x \right )=x$
So, from this property, we can say,
$f\left ( 0 \right )=0$
$f\left ( 1 \right )=1$
$f\left ( 0 \right )\neq f\left ( 1 \right )$
Symmetry Property
It is given
$f\left ( 0 \right )= g\left ( 1 \right )$ and $f\left ( 1 \right )= g\left ( 0 \right )$
$f$ and $g$ working on same value in reverse.
Transitivity Property
Say, $f\left ( 0 \right )=g\left ( 1 \right )=h\left ( 0 \right )=0$
$f\left ( 1 \right )=g\left ( 0 \right )=h\left ( 1 \right )=1$
Now, $f\left ( 0 \right )\neq h\left ( 1 \right )$
So, transitivity property also not satisfied