0 votes 0 votes HeadShot asked Sep 6, 2018 HeadShot 621 views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments arvin commented Sep 6, 2018 reply Follow Share @headshot : it says that there exist some x and there exist some y and they can be anything if we select it from the domain.. i mean they can be same or they can be different.. so if both are different it should have been atleast two. but as there is no condition on selection of x and y. means they can be same so answer should be A. (atleast one is more close to the answer). 4 votes 4 votes HeadShot commented Sep 6, 2018 reply Follow Share Yes "There exist" defined on "+" so it is one or more , so it says "there exist x for atleast one y " hence I also interpreted it as " atleast 2 parents and more possible " But answer given as "D" . Check if its going wrong somewhere. I ll varify the key and write back :) 0 votes 0 votes HeadShot commented Sep 6, 2018 reply Follow Share @arvin Yes, A is correct one. Hey, so if they want to keep x and y distinct will they explicitly mention "^ x !=y " ? Will you frame that statement using FOL ? 0 votes 0 votes Please log in or register to add a comment.
Best answer 4 votes 4 votes Ans : A Since they have not specified that x!=y, it could happen that x and y refer to the same human and the condition becomes true. sakharam answered Sep 6, 2018 selected Sep 6, 2018 by HeadShot sakharam comment Share Follow See all 3 Comments See all 3 3 Comments reply arvin commented Sep 6, 2018 reply Follow Share yes u are right :P 0 votes 0 votes srestha commented Sep 6, 2018 reply Follow Share why not D) I think A) and D) both can be correct 0 votes 0 votes Mk Utkarsh commented Dec 6, 2018 reply Follow Share srestha X be a universe $X= \{a,b,c,d,e,f \}$ all are parents now option $A$ is still valid but option D is invalid 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes The answer is A right because of its appropriate meaning With there exit at least one parent Rackson answered Oct 12, 2018 Rackson comment Share Follow See all 0 reply Please log in or register to add a comment.