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System is like

CPU ->LEVEL1 CACHE -> LEVEL2 CACHE

So effective memory access time

=Hit of level 1 *(Access time of level 1) + (Miss of level 1)(Access of level 1 + access of level 2)

=.95*(10) + 0.05 *(100+10)=15 sec

But in question they asked for AVERAGE ACCESS TIME FOR WORD

so its = Total time /Number of words.

total time = 100*10 + 4900*110= 540000

number of words are 5000

so time = 540000/5000=108.nano sec
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