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In a 32-bit machine we subdivide the virtual address into 4 segments as follows:  10-bi  8-bit  6-bit  8 bit    We use a 3-level page table, such that the first 10-bit are for the first level and so on. Page Table Entry Size is 2B

10-bit

8-bit

6-bit

8 bit

What is the size of a page table for a process that has 256K of memory starting at address 0?

## Here My doubt is -- In outermost Page no entry. Number of bits = 10

That means no of entries in outermost page table can be 2^10 So max size of Outermost page Table is 2^10 * PTE = 2^10 * 2 = 2^11

which is greater than page size which is 2^8 so outer most page cannot fit in one page table

But outermost page table should fit in one page ??

ref:

 

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