0 votes 0 votes closed with the note: Got the answer What is the minimum number of NOR gates required to implement this boolean function? A'B + A'CDB + AC'B + ABC Also how many NAND gates required? Confirm answer am getting zero. Digital Logic digital-logic boolean-algebra min-no-gates + – smsubham asked Sep 8, 2018 • closed Sep 10, 2018 by smsubham smsubham 4.4k views comment Share Follow See all 9 Comments See all 9 9 Comments reply Show 6 previous comments Shaik Masthan commented Sep 10, 2018 reply Follow Share 3 NOR gates for the question AB+C. 0 votes 0 votes Mohit Pandit commented Oct 28, 2018 reply Follow Share On solving we got ' B'. So no nand No nor gate required 0 votes 0 votes G Phalkey commented Jan 25, 2019 reply Follow Share what are the steps to solve such type of questions 0 votes 0 votes Please log in or register to add a comment.
Best answer 4 votes 4 votes ZERO A'B + A'CDB + AC'B + ABC = A'B(1+CD) + AB(C'+C) = A'B(1) + AB(1) = A'B + AB = B(A'+A) = B(1) = B You don't need a NOR Gate to get B as the output. Balaji Jegan answered Sep 8, 2018 • selected Apr 1, 2020 by smsubham Balaji Jegan comment Share Follow See all 0 reply Please log in or register to add a comment.