above data satisfy all conditions
by (ii) Each manager has only one speciality i.e.
managerid -> speciality
(iv) employee has only manager for each speciality
empid,speciality --> managerid
So Primary key will be = (empid,speciality)
managerid -> speciality // 3NF
empid,speciality --> managerid // 3NF
so relation schema may be in 3NF
please correct me if mistakes.