0 votes 0 votes Number of ternary sequences possible with 6 ones ,6 twos and 4 zeros ,so that each 1 is followed by 2 Combinatory combinatory + – sajal singh asked Sep 12, 2018 recategorized Sep 12, 2018 by Mk Utkarsh sajal singh 548 views answer comment Share Follow See all 8 Comments See all 8 8 Comments reply Show 5 previous comments Magma commented Sep 12, 2018 reply Follow Share take example 0 1 2 1 2 1 2 0 given that each 1 is followed by 2 (1 2) (1 2) (1 2) 0 0 = 5! / 3! 2! 1 votes 1 votes Shubhgupta commented Sep 12, 2018 reply Follow Share each one is followed by two and we have 6 one's and 6 two's which can form 6 group and we have 4 0's. then total sequence possible = $\frac{(6+4)!}{6!*4!(because of repetition))}$ 3 votes 3 votes Shaik Masthan commented Sep 12, 2018 reply Follow Share Thanks to Magma and Shubhgupta 0 votes 0 votes Please log in or register to add a comment.