0 votes 0 votes Let $ f(x, y) = \begin{cases} \dfrac{x^2y}{x^4+y^2}, & \text{ if } (x, y) \neq (0, 0) \\ 0 & \text{ if } (x, y) = (0, 0) \end{cases}$ Then $\lim_{(x, y) \rightarrow (0,0)}$$f(x,y)$ equals $0$ equals $1$ equals $2$ does not exist Calculus isi2016-mmamma calculus limits non-gate + – go_editor asked Sep 13, 2018 recategorized Nov 19, 2019 by Lakshman Bhaiya go_editor 419 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply `JEET commented Nov 19, 2019 reply Follow Share A? 0 votes 0 votes neeraj_bhatt commented Sep 7, 2020 reply Follow Share Limit doesn’t exist. 0 votes 0 votes Shiva Sagar Rao commented May 7, 2021 reply Follow Share https://gateoverflow.in/210193/isi-2016-05 0 votes 0 votes Please log in or register to add a comment.