0 votes 0 votes closed as a duplicate of: Made easy test series Consider the following transactions: T₁= w(A);w(B);r(C);Commit T₂= w(B);r(B);Commit The number of schedules of T1 and T2 that are recoverable are_________? Somoshree Datta 5 asked Sep 14, 2018 • closed Sep 14, 2018 by Mk Utkarsh Somoshree Datta 5 347 views comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments Somoshree Datta 5 commented Sep 14, 2018 reply Follow Share How are you getting 30? I got 29 as the answer. But answer is given as 20. How did u solve this? 0 votes 0 votes ad140 commented Sep 14, 2018 reply Follow Share Total concurrent schedule is (4+3)C4 = 35 non recoverable schedule Case 1 when T2 reads from T1 and commits then we have 4 ways to arrange. Case 2 when T1 reads from T2 and commits before we have 1 way. so total is 5. recoverable is 35-5 = 30. Am I correct please check? 0 votes 0 votes arvin commented Sep 14, 2018 reply Follow Share https://gateoverflow.in/219604/made-easy-test-series 0 votes 0 votes Please log in or register to add a comment.