0 votes 0 votes closed as a duplicate of: ISI2017-MMA-14 Let $(v_n)$ be a sequence defined by $v_1=1$ and $v_{n+1}=\sqrt{v_n^2 +(\frac{1}{5})^n}$ for $n\geq1$. Then $\lim _{n\rightarrow \infty} v_n$ is $\sqrt{5/3}$ $\sqrt{5/4}$ $1$ nonexistent Calculus isi2017-mma engineering-mathematics calculus limits + – go_editor asked Sep 15, 2018 • closed May 11, 2019 by akash.dinkar12 go_editor 378 views comment Share Follow See all 0 reply Please log in or register to add a comment.