let us take an example to understand the problem ,if $\left | x \right |> 2$ then solution set of this inequality will be (2,infinity) union (-infinity,2) , similarly we will proceed for this $ x^2-5 x+4 $< -(x^2-5x+4) it implies (x-1)(x-4)<0 which has solution lies in 1<x<4 and the other part $ x^2-5 x+4 $> (x^2-5x+4) has no solution so finally we get option A.