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X=2,3  satisfies the above inequality condition so answer is(D)
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let us take an example to understand the problem ,if $\left | x \right |> 2$ then solution set of this inequality will be (2,infinity) union (-infinity,2) , similarly we will proceed for this $ x^2-5 x+4 $< -(x^2-5x+4) it implies (x-1)(x-4)<0 which has solution lies in 1<x<4 and the other part $ x^2-5 x+4  $> (x^2-5x+4) has no solution so finally we get option A.
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Answer (A):

Case 1: If x$^{2}$-5x+4 > 0 then mod will open with postive sign

               Thus, |x$^{2}$-5x+4 | = x$^{2}$-5x+4 and hence not greater than

                hence case 1 is rejected.

Case 2: If x$^{2}$-5x+4 < 0 then mod will open with negative sign

                x$^{2}$-5x+4 < 0

              $\therefore$  (x – 4)(x – 1) < 0

               So x lies between 1 and 4

1 < x < 4

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