0 votes 0 votes The area lying in the first quadrant and bounded by the circle $x^2+y^2=4$ and lines $x=0 \text{ and } x=1$ is given by $\frac{\pi}{3}+\frac{\sqrt{3}}{2}$ $\frac{\pi}{6}+\frac{\sqrt{3}}{4}$ $\frac{\pi}{3}-\frac{\sqrt{3}}{2}$ $\frac{\pi}{6}+\frac{\sqrt{3}}{2}$ Geometry isi2017-mmamma circle area non-gate descriptive + – go_editor asked Sep 15, 2018 retagged Nov 19, 2019 by Lakshman Bhaiya go_editor 311 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes $Area =\int_{0}^{1} \sqrt(4-x^2)$ which on solving will give option A N answered Apr 11, 2019 N comment Share Follow See all 0 reply Please log in or register to add a comment.