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Consider an IPV4 addressing system,where at same time two multicast groups are ongoing,by choosing their multicast group addresses at random. The probability they interfere each other i.e. choosing same multicast address is ?
asked in Computer Networks by Loyal (6.9k points) | 35 views

1 Answer

0 votes
i think it should be

(1/2^28)*(1/2^28)

 

but it has given (1/2^28) in made easy solutions
answered by (11 points)

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