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asked ago in Computer Networks by Loyal (5.6k points) | 14 views

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(30/6)*(6-4)=5*2=10 MBps
answered ago by Junior (579 points)
selected ago by
Can you explain briefly how u got the result ?
computer A has to send 30MB data to network and it sends data at 6MB rate to the network but routers data transmission rate is 4MB. So have to send data at min(4,6)=4MB to the network.But as computer is sending at 6 mb so each time 2 mb is left in the queue,now computer A has to send 5 times 6MB data so tatal (5*2)MB=10MB willbe there in the queue.
Nice thnx

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