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1 Answer

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In class A: the first bit is 0

the first address = 00000000->0

the last address=01111111->127

so the total address are 2^7=128

but 0.0.0.0 is used requesting ip , and 127.*.*.*  is used for loop back address so (2^7)-2

in class B:the first two bits are 10

so the total network id's possible are: 2^(16-2) = 2^14
Answer:

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