0 votes 0 votes what is difference between this and in questions if asked to find derivative or check differentiable or not, which formula should i use? 1) $lim_{h\rightarrow 0} \frac{f(a+h)-f(a)}{h}$ 2) $lim_{x\rightarrow a} \frac{f(x)-f(a)}{x-a}$ Calculus limits calculus + – Rahul_Rathod_ asked Sep 16, 2018 Rahul_Rathod_ 306 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply BASANT KUMAR commented Sep 16, 2018 reply Follow Share both of them is same because if you replace x by x+a in second eq we will automatically get eq 1.you can use any one of them but for more simplicity you can use eqn (1) 0 votes 0 votes Rahul_Rathod_ commented Sep 16, 2018 reply Follow Share how can we replace x by x+a ? 0 votes 0 votes BASANT KUMAR commented Sep 16, 2018 reply Follow Share let f(x) be x-5 and consider the limit x->1 here a is 1 by replacing x to x+1 then lim become x->0 we must replace x+1 in f(x) now put the value we will get the answer 1 from both method. if lim x->h then we can replace lim x+h->h where h is small quantity after that it become lim x->0.you may refer class 12 ncert book of mathematics. 0 votes 0 votes Kabir5454 commented May 11, 2022 i edited by Kabir5454 May 11, 2022 reply Follow Share Both are actually same. lets take the second one, $\lim_{x->a} \frac{f(x)-f(a)}{x-a}$ now lets assume , $h=x-a$ so as $x->a$ the $h->0$ now , x=h+a , substituting this in the formula, $\lim_{h->0}\frac{f(a+h)-f(a)}{h}$ so, it is the first expression 0 votes 0 votes Please log in or register to add a comment.