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What is the dual of A+A'B=A+B
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dual of (A+A'B) =>  A.(A'+B)=>  AA'+A.B=>  A.B (as AA' = 0)

dual of(A+B) => A.B

so dual of (A+A'B=A+B) => A.B = A.B
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The dual of a Boolean expression is obtained by:

  • Interchanging boolean sum and boolean product (interchange $+, .$)
  • Interchanging the $0’s,1’s$
  • keep the variable as it is.

So the dual of the given expression is:

$A+\bar AB=A+B$

$A.(\bar A+B)=A.B$

$A.B=A.B$ is the dual of the given boolean expression.

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