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A bit string is called legitimate if it contains no consecutive zeros, e.g., 0101110 is legitimate, where as 10100111 is not. Let $a_n$ denote the number of legitimate bit strings of length $n$. Define $a_0=1$. Derive a recurrence relation for $a_n$ (i.e., express $a_n$ in terms of the preceding $a_i$').

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I think a(n)=a(n-1)+2; a0=1
answered by (373 points)

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