1 votes 1 votes If A∆B = (A intersection B) whole complement than the universal set is?? Set Theory & Algebra ace-booklet set-theory&algebra engineering-mathematics set-theory + – Anjali2002 asked Sep 18, 2018 Anjali2002 350 views answer comment Share Follow See all 2 Comments See all 2 2 Comments reply Shaik Masthan commented Sep 18, 2018 reply Follow Share A ∆ B = ( A U B ) - ( A ∩ B ) Given that A ∆ B = ( A ∩ B )' = U - ( A ∩ B ) ====> Universal Set is ( A U B ) 1 votes 1 votes smsubham commented Sep 18, 2018 reply Follow Share The universal set should be $A \bigcup B$. Explanation: We know, $A \Delta B =\left ( A \bigcup B \right ) - \left ( A \bigcap B \right )$ $A \Delta B = \left ( A \bigcap B \right )'$ = Universal Set - $\left ( A \bigcap B \right )$ $\left ( A \bigcup B \right ) - \left ( A \bigcap B \right )$ = Universal Set - $\left ( A \bigcap B \right )$ => Universal Set = $\left ( A \bigcup B \right ) $ 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes Given that A∆B= ( A meet B)'= UNIVERSAL SET - (A meet B) By definition A∆ B= ( AUB)-( A meet B) HHence A∆ B is Universal set. DIBAKAR MAJEE answered Apr 26, 2020 DIBAKAR MAJEE comment Share Follow See all 0 reply Please log in or register to add a comment.