option A:- It has 3 components 20 vertices and 16 edges.
we know that, For k components with n nodes, there should atleast n-k edges.
===> 20-3=17 edges should present, but we have 16 edges ===> This is False
check this for proof https://gateoverflow.in/237427/graph-theory
option B:- It has 10 vertices, 38 edges, and more than one component.
Maximum edges we can get ( with 2 components only due to given that more than one component ).
Keep 1 vertex as one component, remaining all vertices are one component, then maximum edges = complete graph of (n-1) nodes ===> maximum edges = (n-1)C2. ===> 9C2 = 36,
but given that we have 38 edges, therefore given graph is not simple graph.
Option C :- It has 7 vertices, 10 edges, and more than two components.
given that more than 2 components, therefore let check from 3
{1},{1},{5} components ===> Maximum 5C2 =10 edges with {5} component ===> we can have simple graph.
Option D:- It is connected and has 10 edges 5 vertices and fewer than 6 cycles.
It is a complete graph of 5 vertices, Check the cycles
it should be more than 6 ===> Statement is False