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Self doubt Pushdown Automata
Mk Utkarsh
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Theory of Computation
Sep 20, 2018
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Sep 21, 2018
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Mk Utkarsh
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Is it required to initialize stack symbol in PDA?
If yes then does this PDA have valid transitions?
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Mk Utkarsh
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Theory of Computation
Sep 20, 2018
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Mk Utkarsh
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M_Umair_Khan42900
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Theory of Computation
Dec 29, 2022
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Construct pushdown automata that recognize the following language. L= (a²ⁿ b³ⁿ | n ≥ 0}
Construct pushdown automata that recognize the following language. L= (a²ⁿ b³ⁿ | n ≥ 0}
M_Umair_Khan42900
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Theory of Computation
Dec 29, 2022
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M_Umair_Khan42900
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Abhipsa
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Theory of Computation
Jan 22, 2019
203
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Pushdown Automata
Let P be a non-deterministic pushdown automaton (NPDA) with exactly one state, q, and exactly one symbol, Z, in its stack alphabet. State q is both the starting as well as the accepting state of the PDA. The stack is initialized with one Z before the start of the operation ... L(P) is not necessarily ∑* Both L(P) and N(P) is necessarily ∑* Neither L(P) nor N(P) are necessarily ∑*
Abhipsa
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Theory of Computation
Jan 22, 2019
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Abhipsa
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pushdown-automata
theory-of-computation
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anonymous
asked
in
Theory of Computation
Jan 16, 2019
199
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Building a pushdown automata that receives L*
given a pushdown automata that receives L by getting to an accepting state, how can a pushdown automata be built, so that it accepts L*? (might use a “double bottom” if needed)?? i don’t know how to solve it and would appreciate any kind of help! studying for exam and must learn how to solve it
anonymous
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Theory of Computation
Jan 16, 2019
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anonymous
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pushdown-automata
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4
jatin khachane 1
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Theory of Computation
Dec 10, 2018
511
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MadeEasy Subject Test 2019: Theory Of Computation - Pushdown Automata
Options: $\left \{ \left ( b^{n}ab^{n}a\right )^{m} | n,m \geq 0 \right \}$ $\left \{ \left ( b^{n}ab^{n}a\right )^{m} | n,m \geq 0 \right \} \cup \left \{ b^{n} | n\geq 0 \right \}$ $\left \{ \left ( b^{n}ab^{n}\right )^{m}a | n,m \geq 0 \right \}$ $NONE$
jatin khachane 1
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Theory of Computation
Dec 10, 2018
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jatin khachane 1
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Same,easy to moderate
I felt paper was very much like AIMT 3!!
very easy paper, I don't want to discuss paper...
the paper was easy to moderate, in this paper...
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