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Probability - Gravner-3

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Toss three fair coins. What is the probability of exactly one Heads$(H)$ ?
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Toss three fair coins.

Total possibilities are : $HHH$, $HHT$, $HTH$, $HTT$, $THH$, $THT$, $TTH$, $TTT$.

Therefore, there are total $8$ possibilities.

Favourable case (exactly one head) : $HTT$, $THT$, $TTH$

Therefore, there are total $3$ favourable cases out of $8$ possibilities.

P(exactly one Head $(H)$ ) = $\dfrac{3} {8}$

                                            = $\dfrac{\text{Favourable case}} {\text{Total possibilities}}$

                                         = $0.38$
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